A Call to PHP Function on INPUT field is not working
Posted: Thu Dec 13, 2012 10:28 pm
Script URL: localhost
Version of script: 5+
Hosting company: localhost
URL of phpinfo.php: localhost/
URL of session_test.php: localhost/
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Write your message below:
I've written a php function script to check the a default value of a text field during an onFocus and onMouseOut events.
The default value of the text field is 'Search'.
When a user sets focus on the text field, the value should clear to empty string.
When the user removes focus and without entering a text, the value should be set back to 'Search'.
Else a $value variable should be assigned the value of the user input in the text field.
Please see the code below and help me out - cos, I am having problem calling the script on the input field. I'm not even sure whether the script is wrong or not...
Thank you!.
Version of script: 5+
Hosting company: localhost
URL of phpinfo.php: localhost/
URL of session_test.php: localhost/
What terms did you try when SEARCHING for a solution:
Write your message below:
I've written a php function script to check the a default value of a text field during an onFocus and onMouseOut events.
The default value of the text field is 'Search'.
When a user sets focus on the text field, the value should clear to empty string.
When the user removes focus and without entering a text, the value should be set back to 'Search'.
Else a $value variable should be assigned the value of the user input in the text field.
Please see the code below and help me out - cos, I am having problem calling the script on the input field. I'm not even sure whether the script is wrong or not...
Code: Select all
<?php
function setValue()
{
if (!empty($_REQUEST['qfront']) && $_REQUEST['qfront']=='Search')
{
$value=''; //$_REQUEST['qfront']="";
}
elseif (!empty($_REQUEST['qfront']) && $_REQUEST['qfront']!='Search')
{
$value=$_REQUEST['qfront'];
}
else //if (empty($_REQUEST['qfront'])
{
$value='Search';
}
return setValue();
}
?>